The watt rating is based on full load current, so the 370 W power consumption when in full leitourgia.Kata start-up, the power consumption is much more, as the rotor speed, but should be reduced to 370 watts, just reaches its maximum tachytita.Analoga the cost of electricity, you should cost about 2-3 cents per hour to operate, or $ 15-20/month if you run 24 / 7

A 370 Watt motor consumes 370 Watts.Kata start or overload uses a lot more, maybe less if diplasio.Kapos ekfortonontai.Matia edo
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|http://www.LTD. Rabbits. Gov/cneaf/electricity/epm/table5_6_b.htmlgia get an idea if you do not know what plironete.Pollaplasiazoume in 3241. 2 KWh for an annual cost

370 Watt

The nominal power is the continuous assessment. Starting power is understood to be higher, but certainly short lived. National Electrical Code has information on different types of engines starting surges of X times the continuous power. I think induction is 2 times, and household split phase motors tend to be 3 horsepower rating fores.I half incredibly amazing in conjunction with the rated power. This means that the motor is 99. 19% effective.

Almost certainly the result of multiple roundings. (Note that the efficiencies of 95% in very expensive machines, such as 200 or more horsepower. See
|http://www.Energy. Wsu. Ed/uftp-e/ppub/smechanica/lengin/eefficiencyStandards.pdf)

370 W is the power load rating using the engine. When idling will be less. In the event that load that would require the motor to use more than 370W in danger of burning out (there is often a safety margin).

clear the confusion As.I rating plate 0. 5HP and 370W express mechanical power output (or power line) that the motor will deliver a load when operating in namplate voltage, input frequency and output speed. From wikipedia: “The plates for electric motors show their power, not their validity.” Http://en. Wikipedia.Or/gwik/iippodynamiApo 1 HP is set to 746W, we get: 0. 5HP x 746W/HP = 373W or 370W strongylemenesEtsi both 0. 5HP and 370W for the same parameter, power kinitira.Den engine is 100% effective, so the input power is higher than the output power. Single-phase, fractional horsepower motors (<1HP, <746W) have bad efficienies. For example, what Leeson 1/2HP motor has a nominal yield of 61% to 100% load and low efficiency at lower loads (Click the "Performance" tab):
|http://www.Baymotorwinding.com/inventory/listings/details/index/staticcfm/adnum/1041926000.htmStin case of submersible pumps for wells, improved vehicle efficiency is usually much lower for a given size engine. May be due to the pressure, the motor has to fit in a small diameter well casing.

It could also be due to motor manufacturer can get away with producing a low-powered performance of the liquid in which the motor is submerged will carry away the waste heat.

And submersible motors tend to be excluded from performance requirements.

It is difficult to find any evaluations of effectiveness published in moter.Etsi submarines would not be surprised if a submarine engine was about 50% apotelesmatiko.Gia to answer your question, if the engine had operated at full load for one year will spend the following energy input (to yield 50%): 373/w 0. 50eff x 1kW/1000W x 8760hr/yr = 6535 kW/hetosStis U.S., a typical rate would be $ 0. 13/kWh.

The cost will be: 6535 kW/hyear x $ 0. 13/kWh = US $ 850/yrEinai likely that the pump and the engine may not be operating at full load, so the cost will be mikrotero.I curve of the pump (supplied by the manufacturer) will be very useful in predicting required ippodynami.Elpizo that helps.